OK, I've tried to do this just now using an anonymous subroutine, but I'm getting strange error messages. Here is my code:

my $command = sub { \@returnstring = \$d->checklist( text => $text, li
+st => [ @list ] ) };
&$command;

[download]

Here is the error:

Can't modify reference constructor in scalar assignment at ./cdialog.p
+l line 43, near ") }"
Execution of ./cdialog.pl aborted due to compilation errors (#1)
    (F) You aren't allowed to assign to the item indicated, or otherwi
+se try
    to change it, such as with an auto-increment.

Uncaught exception from user code:
        Can't modify reference constructor in scalar assignment at ./c
+dialog.pl line 43, near ") }"
Execution of ./cdialog.pl aborted due to compilation errors.

[download]

Here's an update:

Here's the code I'm running now:

my $command = sub {
        $d->checklist( text => $text, list => [ @list ] );
};

my @returnlist = $command->();

[download]

And here's the error:

Can't use string (",") as an ARRAY ref while "strict refs" in use at
        /usr/local/lib/perl5/site_perl/5.8.3/UI/Dialog/Backend/CDialog
+.pm line 581 (#1)
    (F) Only hard references are allowed by "strict refs".  Symbolic
    references are disallowed.  See perlref.

[download]

Also, in case it matters, list contains exactly this:

'1' , [ 'item1' , 0 ] , '2' , [ 'item2' , 0 ] , '3' , [ 'item3' , 0 ] , '4' , [ 'item4' , 0 ] , '5' , [ 'item5' , 0 ] , '6' , [ 'item6' , 0 ]

Janitor note: Original content follows:

Hello All-Knowing Monks,

I need to execute a command that I have built in a variable, like this: 

my $command = "my \@returnstring = \$d->checklist( text => $text, list
+ => [ @list ] );";

[download]
If I print out the contents of $command I get exactly the line I want to execute, which looks like this: 
my @returnstring = $d->checklist( text => Text, list => [ '1' , [ 'ite
+m1' , 0 ] , '2' , [ 'item2' , 0 ] , '3' , [ 'item3' , 0 ] , '4' , [ '
+item4' , 0 ] , '5' , [ 'item5' , 0 ] , '6' , [ 'item6' , 0 ] ] );

[download]
But if I put $command; on a line by itself, the contents of $command are not executed as a statement. Is there any way to make the contents of $command execute as a statement?

Thanks in advance for any help!

In reply to Probably an easy one - store command in variable. by rementis

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