overload doesn't define operators; it redefines them. ?= would have to be added to perl by patch.

There is an alternative to a new or overloaded operator. One could use a tied hash. The only difference would be in the setter.

By the way, my function does not autovivify. At least, not in 5.6.x or 5.8.x.

In reply to Re^5: Shortcut operator for $a->{'b'}=$b if $b; by ikegami
in thread Shortcut operator for $a->{'b'}=$b if $b; by rokadave

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