It's a substitution operator. It is telling perl to find every occurrence of "%" in $box, and replace it with "%%".

See perlrequick and perlre for information on how regular expressions and substitutions work. You will find additional info in perlop under the m// and s/// operators.


Dave

In reply to Re: regular expression: what does $box =~ s/%/%%/g; mean? by davido
in thread regular expression: what does $box =~ s/%/%%/g; mean? by tphuang

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