You can rewrite 
my $dum=$1; my $val; if ($dum) { $val = $value * $dum }else{ $val=$val
+ue} $val

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To be ($1 != 0)? ($value * $1) : $value like prasadbabu had it, or really it can just be boiled down to: 
$value * ($1 || 1)

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(Assuming that $value is alway numeric) No need for a temp variable or the explicit if/else.

also, since you're not chomp'ing $line, that "\n" in your print line is going to going to double-space the output...

In reply to Re^2: Evaluating a regex replacement value by davidrw
in thread Evaluating a regex replacement value by McDarren

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