No, it is not the result of number-to-string conversion. Consider the following: 
my $x = 100000000000000;
for my $ii (14..25) {
    print("10^$ii: ", 0 + $x, "\n");
    $x *= 10;
}

[download]
which outputs: 
10^14: 100000000000000
10^15: 1000000000000000
10^16: 10000000000000000
10^17: 100000000000000000
10^18: 1000000000000000000
10^19: 10000000000000000000
10^20: 1e+20
10^21: 1e+21
10^22: 1e+22
10^23: 1e+23
10^24: 1e+24
10^25: 1e+25
This shows that Perl can output 20-digit integers, and verifies that the integer return value is being coerced into a floating-point result by the overload handling code.

Remember: There's always one more bug.

In reply to Re^2: Numeric overloading with 64-bit Perl by jdhedden
in thread Numeric overloading with 64-bit Perl by jdhedden

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