Hello, Whenever I use undef on a large hash, everything that follows that undef becomes slower. Here is an example:
######################## #! /usr/local/bin/perl use strict; { my $i = 0; my ; my %testHash2; my $max = 1000000; my $startTime = time; print "Loading hash 1...\n"; for($i = 0; $i <= $max; $i++){ $testHash1{$i} = "THIS IS MY $i PROTEST SONG"; if($i%100000==0){ print "Loaded $i\n"; } } my $stopTime = time; printf("Hash 1 Rows/Sec: %.01f\n",$i/($stopTime-$startTime)); undef %testHash1; $i = 0; $startTime = time; print "Loading hash 2...\n"; for($i = 0; $i <= $max; $i++){ $testHash2{$i} = "THIS IS MY $i PROTEST SONG"; if($i%100000==0){ print "Loaded $i\n"; } } $stopTime = time; printf("Hash 2 Rows/Sec: %.01f\n",$i/($stopTime-$startTime)); } ##############
On my machine, the inserts to %testHash1 takes place at about 250,000 recs/second. The second insert to %testHash2 inserts at a rate of about 9000 recs/second. If I remove the undef %testHash1. The second batch of inserts is just as fast as the first. I have tried emptying the hash in different ways (%testHash1 = ();...) but the results are always the same. What am I doing wrong? Thanks, Thalej

2005-10-12 Retitled by g0n, as per Monastery guidelines
Original title: 'perl undef'


In reply to Use of undef slowing down perl? by thalej

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