Another possibility:

$count{$1}++ while $seq =~ /(?=(.{1}))/g;
$count{$1}++ while $seq =~ /(?=(.{2}))/g;
$count{$1}++ while $seq =~ /(?=(.{3}))/g;

[download]

Update: woops, added the (?=) I initially forgot.

In reply to Re: Question about speeding a regexp count by ikegami
in thread Question about speeding a regexp count by Commander Salamander

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