Does the symbol $user appear somewhere outside of the loop? Its scope is constrained to inside the loop. If you try to access $user outside the loop you'll get a fatal error under strictures.

Also check to ensure that the line preceeding your for loop isn't missing a semicolon at the end of the line. ;)


Dave

In reply to Re^2: Sorting data structure by davido
in thread Sorting data structure by mhearse

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