To find out which character it is (assuming it's the last character in the line), do
printf("%X", ord(substr($line, -1)), "\n");
Use that number instead of ### to remove that character along with whitespace:
$line =~ s/[\s\x{###}]+$//;
Of course, you could remove all trailing control characters and whitespace:
$line =~ s/[\s\x00-\x1F\x7F]+$//;
There's also a "print" character class that could help you, I believe.

By the way, \r is included in \s:

$line = "\n";
print(length($line), "\n");
$line =~ s/\s+$//;
print(length($s), "\n");

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In reply to Re: When is a trailing space not a trailing space? by ikegami
in thread When is a trailing space not a trailing space? by markguy

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