I like this !! based solution the best. It's the most logical way to solve the problem - convert the arguments to boolean truth values, then sum them. You could do it for an arbitrarily long list of variables with: 
use List::Util qw( sum );

if( 1 == sum( map { !!$_ } @inputs) ) {
   ... 
}

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In reply to Re^2: One out of three ain't bad (order) by ph713
in thread One out of three ain't bad by saintmike

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