I have this code:

foreach $row (@array) {
  &routine($row);
}

sub routine {
  if ($row != '10') {
    print "stuff";
  } else {
    next;
  }    
}

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When I'm running it and hit a value of "10" I get a message saying "Exiting subroutine via next"

Is there a way to get the "foreach" loop to go to the next array element from within the subroutine?

Or do I have to "return" a value from the subroutine, then "next" from within the "foreach" loop that way? Is there a better way to do this?

In reply to next'ing out of a "foreach" loop within a subroutine by awohld

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