Quote from self: in a eval statement probably, I don't know

eval "
[...]
s${regexpand}foobar/;
[...]
";

[download]
This code wil validly substitute any of those three words at the beginning of a string and before a word boundary with 'foobar'. I see no reason for doing this but it is perfectly valid.
Unless I'm completely wrong of course :p

In reply to Re^3: what does this regex do? by muba
in thread what does this regex do? by moltar512

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