It does look temptingly simple doesn't it?

But you'd be iterating across the list three times - which isn't very efficient. You only really need to iterate across it once. Something like this (off the top of my head and untested).

# use 'mean' instead of 'avg' as it's unambiguous
sub min_max_mean {
  my ($min, $max, $tot);
  my $count = @_;
  $min = $max = $tot = shift;

  foreach (@_) {
    $min = $_ if $_ < $min;
    $max = $_ if $_ > $max;
    $tot += $_;
  }

  return ($min, $max, $tot / $count);
}

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In reply to Re^2: minimum, maximum and average of a list of numbers at the same time by davorg
in thread minimum, maximum and average of a list of numbers at the same time by LucaPette

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