No matter where you put the third point of the second group, other than on that line, the problem is insoluble. I think?
No. The line you have drawn has one x on the left of the line, and one x on the right of the line - since 1 is not more than half of 3, it correctly divides the set of x points. And no matter where you place the third point, each half-plane (that is, right of the line, or left of the line) contains at most 1 point.

Points that are on the line are neither to its left, nor to its right.

Perl --((8:>*

In reply to Re^6: Puzzle: The Ham Cheese Sandwich cut. by Perl Mouse
in thread Puzzle: The Ham Cheese Sandwich cut. by Perl Mouse

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