Sentient saints,

I have 3 stacks: %current, %previous, and %output.

For easy debugging, I have this: 

require Data::Dumper if $^P;

#...lots of code...

my %output; ### The information that was output last
my %current; ### The current record's information
my %previous; ### The previous record's information

### Now that these variables are in scope, create a closure
### that we can use for debugging. This prints all 3 stacks.
    
my $stack = sub {
    print Data::Dumper->Dump(
        [\%previous, \%output, \%current],
        ['*previous', '*output', '*current']
    );
};

[download]
Therefore, Data::Dumper is loaded when debugging, and a simple "x $stack->();" shows all 3 stacks.

I understand that a closure can see all of the lexicals that exist when it is defined, which leads to my question. Many lexicals exists (~50) when this closure is created. Are there any negative effects to closing around many lexicals, or is this another instance of Perl "magic" that ultimately makes no difference? Maybe I should "our" these and create a normal routine...

Thanks once again for satiating my curiosities.

In reply to Wide open Closures? by eff_i_g

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