And everyone is going to have to learn the other way for perl 6 because lexicals spring into existence immediately upon being parsed (not the whole statement, just the variable). So, in this code: 

my $x = $x + 5;

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Both $x refer to the same storage location (the same variable). To get the perl5 behavior you have to say something like: 
my $x = $OUTER::x + 5;

[download]

duff

In reply to Re^3: Iterative anonymous subroutines by duff
in thread Iterative anonymous subroutines by Anonymous Monk

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