Did you notice a pattern in the table you pasted? It looks like it contains all the information you need. It's basically like this:

If $x%3 is 0, the arrays should all be of size $x/3. If $x%3 is not 0, there should be $x-($x%3) arrays of size $x/3 and $x%3 of size $x/3+1.

I'm not positive this will continue to hold true, but it looks good from what you've shown. There may be a simpler algorithm too, so I would be happy to see other replies. :-)

In reply to Re: breaking an array into nearly equal parts by revdiablo
in thread breaking an array into nearly equal parts by santonegro

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