it may become less efficient...

It may, or it will? I guess what I am asking is, when does it pay to do the S.T. and why? Does it pay in this case? (I mean, if the data set was a lot larger?)

UPDATE: Maybe an answer at Re: When does it pay to use the schwartzian transform?

In reply to Re^2: Sorting an array on two computed fields by tphyahoo
in thread Sorting an array on two computed fields by jesuashok

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