It "pays" when the cost of pre-computing the sort keys for all of your elements is significantly less than re-computing the sort keys each time you make a comparison. It depends on the cost of computing a sort key, and the number of elements.

In reply to Re: When does it pay to use the schwartzian transform? by runrig
in thread When does it pay to use the schwartzian transform? by tphyahoo

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