Greetings all,
open(LOG,"test.txt");
my $pattern = '(\s+\w+\s+\d{2}\s\d{4}) |  (Release\s+\d+\.\d+)';
while(<LOG>) {
  print $1  if($_ =~ /($pattern)/ );
}

[download]

My  test.txt contains 
__DATA__
December 15 2005

some line 

Flat File Release 100.0

someline

[download]
I can't able to get the 'December 15 20005' value. please suggest any other pattern or why it's not returning?. I guess, either one of the pattern should match and it'll reflect in the  $1.

-kulls

2005-12-20 Retitled by g0n, as per Monastery guidelines
Original title: 'RegExp'

In reply to Regexp for extracting date by kulls

Title:
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