Dear Masters,
I have a code that takes two arguments as input.
The construct I have in my code is as follow:
my $based_on = $ARGV[0] ? shift: 'tp';
my $top = $ARGV[1] ? shift: 1;
print "$based_on $top\n";
# Then the rest of the code
- $ARGV[0] may take value of: "tp" (default) or "sn".
- $ARGV[1] may take value of: 1 (default) to 5.
What I intend to do is to run the code in the following
way:
neversaint$ perl mycode.pl sn 5
But why the print out result of mycode.pl produces: "sn 1"
instead of "sn 5"?
i.e. it fails to capture the second
passed argument.
Is there anything wrong with the construct in my code snippet above.
---
neversaint and everlastingly indebted.......
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