my $based_on = $ARGV[0] ? shift: 'tp';
my $top      = $ARGV[0] ? shift: 1;#change here
print "$based_on $top\n";

# Then the rest of the code

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The problem is that when use use shift you are removing the first element of the array therefore after the shift the second arg is the first in the @ARGV list.

In reply to Re: Ternary Operator for Multiple Arguments Passing by neosamuri
in thread Ternary Operator for Multiple Arguments Passing by neversaint

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