How do I access the array without the intermediate $h_aref?# a hash holding a reference to the array my %hash; print '$aref is ' . $aref ."\n"; $hash{'aref'} = $aref; print '$hash{\'aref\'} is ' . $hash{'aref'}. "\n"; # get h_ version of array reference my $h_aref = $hash{'aref'}; print 'array length is ' . scalar(@$h_aref) . "\n"; push @$h_aref, 'value 2'; print 'after 2nd push array length is ' . scalar(@$h_aref) . "\n"; print 'after 2nd push [0] array value is [' . $$h_aref[0] . "]\n"; print 'after push [1] array value is [' . $$h_aref[1] . "]\n"; # now try to access without intermediate $h_aref #print 'array length is ' . scalar(@$hash{'aref'}) . "\n"; # error #print 'array length is ' . scalar(@$$hash{'aref'}) . "\n"; # error
my %hash; print '$aref is ' . $aref ."\n"; $hash{'aref'} = $aref; print '$hash{\'aref\'} is ' . $hash{'aref'}. "\n"; # get h_ version of array reference my $h_aref = $hash{'aref'}; print 'array length is ' . scalar(@$h_aref) . "\n"; push @$h_aref, 'value 2'; print 'after 2nd push array length is ' . scalar(@$h_aref) . "\n"; print 'after 2nd push [0] array value is [' . $$h_aref[0] . "]\n"; print 'after 2nd push [1] array value is [' . $$h_aref[1] . "]\n"; # now try to access without intermediate $h_aref #print 'array length is ' . scalar(@$hash{'aref'}) . "\n"; # error #print 'array length is ' . scalar(@$$hash{'aref'}) . "\n"; # error print "now without the intermediate \$h_ref\n"; print 'array length is ' . scalar(@{$hash{'aref'}}) . "\n"; push @{$hash{'aref'}}, 'value 3'; print 'array length after 3rd push is ' . scalar(@{$hash{'aref'}}) . " +\n"; print 'after 3rd push [0] array value is [' . $hash{'aref'}[0] . "]\n" +; print 'after 3rd push [1] array value is [' . $hash{'aref'}[1] . "]\n" +; print 'after 3rd push [2] array value is [' . $hash{'aref'}[2] . "]\n" +;
In reply to accessing array through array reference in hash by puff
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