Dear Masters,
My code below can capture a base name of a file that comes without path 
my $file = "somename.out";
my $name     = ( split( /\./, $file ) )[0];
print "$file - $name\n"; 

# This prints "somename" correctly

[download]
How can I generalize my regex above when the file name comes with one or more path: 
my $file_with_path = "path/somename.out" # or
my $file_with_path2 = "path/path2/somename.out"

[download]
Such that it yields the same result: somename

---
neversaint and everlastingly indebted.......

In reply to Capturing Base Name of a File With or Without Path by neversaint

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