-d $s and $s = abs_path($s) or return -1 ; 
  -d $d and $d = abs_path($d) or return -1 ;

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Don't write the same code twice. Ever. :) 
  -d $_ and $_ = abs_path($_) or return -1 for $s, $d;

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Except that's using "foo AND bar OR bletch" where it should be using "foo ? bar : bletch", so I'd tighten that up to: 
 (-d $_) ? ($_ = abs_path($_)) : (return -1) for $s, $d;

[download]

-- Randal L. Schwartz, Perl hacker

In reply to Re: Re: Test to see if directories are the same by merlyn
in thread Test to see if directories are the same by Ovid

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