The square brackets ([]) delimit a character class, which essentially means "match any of these characters". So in your example, the regex ([^to ]|[^from ]) would match any character that is not (because of the ^ character which negates the character class) one of the characters f,m,o,r,t or a space.
You can use simple alternation to match either of these words:
if $line !~ /train times (?:to|from)\b/ {
# do something with line
}
Update: added word boundary \b, thanks to GrandFather for pointing this out :-)
There are ten types of people: those that understand binary and those that don't.
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