Hm, I think I see now what you mean. You can access $_
2 in that line I posted but not after that line was processed.
AFAIK, perl replaces all variables first (like $_
2) and
then processes the commands (like shift). That would result in:
First $_
2 was replaced with it's value (3 or 5 or whatever), and then perl uses the shift command and there is no $_
2 no more..
Maybe that helps!?
Regards, octopus
--
GED/CC d-- s:- a--- C++(+++) UL+++ P++++$ L++>++++ E--- W+++@ N o? K? w-- O- M-(+) V? !PS !PE !Y PGP+(++) t-- 5 X+ R+(+++) tv+(++) b++@ DI+() D+ G++ e->+++ h!++ r+(++) y+
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