I don't want to start arguing over this, but I read that section in perlipc, and it dosn't say that pipes are created with socketpair. It says that socketpair is preferred for bidirectional communication , over 2 pipe pairs. The name, "pipe2" may be misleading.
....snip...... # pipe1 - bidirectional communication using two pipe pairs # designed for the socketpair-challenged ...snip....... But you don't actually have to make two pipe calls. If you have the +socketpair() system call, it will do this all for you. #!/usr/bin/perl -w # pipe2 - bidirectional communication using socketpair # "the best ones always go both ways"

So you are not creating a pipe with socketpair, that is why I brought it up in my original post, about you relating a SIG{PIPE} to the socketpair. I was thinking that somewhere in your program, you had a pipe ( liked a piped open ) which prints to the socket.

It really would be good if you could show a snippet of code which gives your error. Does the code in perlipc (pipe2), showing how to use a socketpair, work OK for you? It works OK for me. How does your code differ from it?


I'm not really a human, but I play one on earth. flash japh

In reply to Re^3: SIG{'PIPE'} and pipe timeout by zentara
in thread SIG{'PIPE'} and pipe timeout by Marcello

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