I'm using List::Compare to compare the Arrays in a Hash of Arrays. I can specify each array in the hash spicifically but since the hash may contain anywhere from 1 to 5 arrays, I'd like to pass all the arrays, without specifiying them, into the List::Compare constructor all at once using just the hash itself.

I've read the documentation for List::Compare but I can't figure it out.

Instead of constructing it like this:
List::Compare->new( \@{$hash{0}}, \@{$hash{1}}, \@{$hash{2}} );

I'd like consruct it like this just using the hash:
List::Compare->new( \%hash );

Here's the full code:

#!/usr/bin/perl -w

use strict;
use List::Compare;

my @primary = qw( 1 2 3 4 );
my @secondary = qw ( 3 4 5);
my @another = qw ( 4 5 6 7 );

my %hash;
$hash{0} = \@primary;
$hash{1} = \@secondary;
$hash{2) = \@another;


my $lc = List::Compare->new( \@{$hash{0}}, \@{$hash{1}}, \@{$hash{2}} 
+);

# Would like to pass and compare every array in the hash without speci
+fying each array in the hash.
# my $lc = List::Compare->new( %hash );
#  But I can't figure out how to get it to work

my @intersection = $lc->get_intersection;

print @intersection;

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In reply to Comparing multiple arrays in Hash of Arrays using List::Compare by awohld

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