Not very satisfying as a solution, but it works.
#! perl -slw
use strict;
m[
(?:^[^0]*0[^0]*0[^0]*$)|
(?:^[^1]*1[^1]*1[^1]*$)|
(?:^[^2]*2[^2]*2[^2]*$)|
(?:^[^3]*3[^3]*3[^3]*$)|
(?:^[^4]*4[^4]*4[^4]*$)|
(?:^[^5]*5[^5]*5[^5]*$)|
(?:^[^6]*6[^6]*6[^6]*$)|
(?:^[^7]*7[^7]*7[^7]*$)|
(?:^[^8]*8[^8]*8[^8]*$)|
(?:^[^9]*9[^9]*9[^9]*$)
]x and print for '0000' .. '9999';
Update: ... but only for 4 digit numbers. By inverting the logic and only printing numbers that don't contain 3 repeated digits, it should work for numbers of any length.
#! perl -slw
use strict;
m[
(?:[^0]*0[^0]*0[^0]*0[^0]*)|
(?:[^1]*1[^1]*1[^1]*1[^1]*)|
(?:[^2]*2[^2]*2[^2]*2[^2]*)|
(?:[^3]*3[^3]*3[^3]*3[^3]*)|
(?:[^4]*4[^4]*4[^4]*4[^4]*)|
(?:[^5]*5[^5]*5[^5]*5[^5]*)|
(?:[^6]*6[^6]*6[^6]*6[^6]*)|
(?:[^7]*7[^7]*7[^7]*7[^7]*)|
(?:[^8]*8[^8]*8[^8]*8[^8]*)|
(?:[^9]*9[^9]*9[^9]*9[^9]*)
]x or m[(?=(\d).*\1)] and print for '000000' .. '999999';
Examine what is said, not who speaks -- Silence betokens consent -- Love the truth but pardon error.
Lingua non convalesco, consenesco et abolesco. -- Rule 1 has a caveat! -- Who broke the cabal?
"Science is about questioning the status quo. Questioning authority".
In the absence of evidence, opinion is indistinguishable from prejudice.
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