Simpler than scalar(): ? '*'x8 : ' 'x8

Randomly, you will not see this problem in perl6: in it the operator x treats its LHS as a scalar and the analagous operator xx treats its LHS as a list.

In reply to Re: On Solving a Simple Problem, and Appreciating the Complexity of Perl by ayrnieu
in thread On Solving a Simple Problem, and Appreciating the Complexity of Perl by liverpole

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