perl does implicit locking of shared variables each time they are accessed, chiefly to avoid perl's internal data structures from getting corrupted. However, perl will not protect a variable across multiple accesses; for example, $i++ involves a read followed by a write. In between, another thread may have modified the variable. The following code was run on a 4 CPU machine: 
#!/usr/bin/perl -w

use threads;
use threads::shared;

my $i : shared = 0;

push @t, threads->new( sub { $i++ for 1..100_000 } ) for 1..4;
$_->join for @t;
print "i=$i\n";



$ perl588t /tmp/p
i=139728

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Dave.

In reply to Re: does an explicitly shared variable need locks? by dave_the_m
in thread does an explicitly shared variable need locks? by gautam

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