I'm building a user interface to run a bunch of queries. It uses a subroutine to prep the data then calls a subroutine that does the query. I want to return just the $ref to the calling subroutine so I can manipulate the table differently depending on the type of query/data. Looping thru @$ref inside the query subroutine works great... 
my $ref = $sth->fetchall_arrayref;

for my $rec (@$ref){
  $query_results .= "<tr>";
  no warnings;
  for my $field (@$rec)
    {$query_results .= "<td>$field</td>"; }
  $query_results .= "</tr>";    
}
$sth->finish();
$dbh->disconnect();
return($query_results);

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However, when I try to return the $ref to the calling subroutine and process it there, I get no data. In fact, I don't even get any table cells. Your help is greatly appreciated. 
my $ref = &select_query($sqlstatement);

for my $rec (@$ref){
  $query_results .= "<tr>";
  no warnings;
  for my $field (@$rec)
    {$query_results .= "<td>$field</td>"; }
  $query_results .= "</tr>";    
}

[download]

In reply to How to return $ref from: $ref = $sth->fetchall_arrayref; by hipnoodle

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