How would I write the regular expression - if (grep(/^$check!/,$_)) $check = file.zip. I need strip the .zip off within the grep. So it would look like if (grep(/^file!/,$_)) with no .zip in the grep.
#!/usr/bin/perl my $scr = "/home/scr/Linux"; my $dest = 1; my $genlist = "$scr/genlist"; my $newlist = "/$scr/Packages/Disk$dest/newlist"; opendir(DIR,"$scr"); @dir_list = grep(/^DVD\d+$/,readdir(DIR)); closedir(DIR); foreach $dir (@dir_list) { opendir(DIR,"$scr/$dir/Packages"); @file_list = grep(!/^\.\.?$/,readdir(DIR)); system("mkdir -p $scr/DVD1/Packages/Disk$dest"); open (LOG, ">$newlist"); foreach $check (@file_list) { open (LIST, "$genlist"); while (<LIST>){ chomp; if (grep(/^$check/,$_)) { print LOG "$_\n"; } } } $dest++ } close (LIST); closedir(DIR);

In reply to Question about grep by ckaspar

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