Hi, I'm trying to do some troubleshooting on a hash, so am trying to figure out what the scalar function (without keys) does:

For instance, the following code

#!/usr/bin/perl use Data::Dumper; %h = ( 1 => "one", 2 => "two", 3 => "", 4 => "four", # 5 => "five", ); print "h is " . scalar %h . "\n"; print "Dump is " . Dumper(\%h);
yields
# perl test.pl h is 4/8 Dump is $VAR1 = { '1' => 'one', '2' => 'two', '3' => '', '4' => 'four' };
So, from experimenting with this code by commenting out elements in %h, I figure the first value is the number of keys, but I'm not sure what the second value is. It stays at 8 no matter what I change. I remember vaguely it has something to do with how densely the hash is populated.... Can anybody tell me what it is?

-- Burvil


In reply to Effect of scalar function on hash by bowei_99

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