To make it change, force perl to make more buckets by adding more items to the hash.
>perl -le "for ('a'..'z') { $h{$_}=1; print scalar %h } 1/8 2/8 3/8 4/8 5/8 6/8 7/8 8/16 9/16 10/16 11/16 12/16 13/16 14/16 15/16 16/32 17/32 18/32 19/32 20/32 21/32 22/32 23/32 24/32 25/32 26/32
Note that sometimes, buckets will be reused:
>perl -le "for ('a'..'z') { $h{$_ x 2}=1; print scalar %h } 1/8 2/8 3/8 4/8 5/8 6/8 7/8 8/16 9/16 10/16 11/16 12/16 13/16 14/16 15/16 <- before adding 'pp' 15/16 <- after adding 'pp' 15/16 15/16 15/16 15/16 21/32 21/32 21/32 21/32 21/32 21/32
Note the duplicate '15/16's. 'pp' was added to an existing bucket because 'pp' hashed to the same value as another key.

In reply to Re: Effect of scalar function on hash by ikegami
in thread Effect of scalar function on hash by bowei_99

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