Since >= and < took almost exactly the same amount of time, I conjectured that $foo >= $bar might get translated to $bar < $foo by the compiler, but this appears to not be the case:
But then, $foo >= $bar is actually equivalent to $bar <= $foo, so you don't gain anything by doing the conversion. :)
In reply to Re: Benchmarking the basic operations
by chipmunk
in thread Benchmarking the basic operations
by Falkkin
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