You were really close -- change "char" to "chr", add "e" at the end, and drop the dash between 9 and A:
perl -i.bak -pe 's/\%([0-7][0-9A-F])/chr(hex($1))/ge'
Bear in mind that values %00-%1F and %7F won't be things that you can "read" very well -- in fact, if you encounter %0D without an adjacent %0A, the resulting display could be very misleading. You might want to limit the regex to:
s/\%([2-6][0-9A-F]|7[0-9A-E])/chr(hex($1))/ge

In reply to Re: Command Line Regex by graff
in thread Command Line Regex by ramblinpeck

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