The question is how to get the $var variable into the perl code since I apparently can not get in is as regular argument while using the -e parameter.
Of course you can. There is no need for @ARGV to only contain a files list. 
perl -le 'print shift' foo

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If the variable contains spaces, you may have to quote it.

You can even combine this with a file list passed as parameters: 

perl -e '$x = shift; while (<>) { print "$x: $_" }' $2 $1

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or even 
perl -nle 'BEGIN { $x = shift } print "$x: $_"' $2 $1

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In reply to Re: arguments to perl -e by bart
in thread arguments to perl -e by olecs

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