It seems to work if you undefine *foo instead of undefining $x. If you want to undefine something, you have to undefine it (and not undefine something else). 

print "Undefining foo()";
undef *foo;
print "Foo is not defined" unless defined &foo;

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brian d foy <brian@stonehenge.com>
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In reply to Re: undefing *foo{CODE} does not fully work by brian_d_foy
in thread undefing *foo{CODE} does not fully work by jesuashok

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