Context, with parens you assign to a list. It does not matter in your case, but:

my $foo = 'bah' =~ /(a)/;
print "$foo\n";
($foo) = 'bah' =~ /(a)/;
print "$foo\n";

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In reply to Re: scalars in parens ? by lidden
in thread scalars in parens ? by Anonymous Monk

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