$a[4,5,6] is the same as $a[6], because the subscript is in scalar context (due to the $)
qw/a b c/ is turned into ('a', 'b', 'c') at compile-time, which in scalar context returns 'c'
Jeff japhy Pinyan,
P.L., P.M., P.O.D, X.S.:
Perl,
regex,
and perlhacker How can we ever be the sold short or the cheated, we who for every service have long ago been overpaid? ~~ Meister Eckhart