That should be fairly easy, since there are always going to be 365 or 366 days in any year between 1900 and the present.  Besides which, the algorithms for calculating whether a year is a leap year or not is trivial.

Have you thought about just writing your own subroutine to do it?

s''(q.S:$/9=(T1';s;(..)(..);$..=substr+crypt($1,$2),2,3;eg;print$..$/

In reply to Re: subroutine for calculating day since 1900 needed by liverpole
in thread subroutine for calculating day since 1900 needed by Anonymous Monk

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