hi monks

I have a little confusion in the below code's behaviour. I found that the builtin variable $& is not having the reliable value in it. Initially I tried to print the values available in $` and $'. but I found a misleading answer when I print $&.
I picked this code from a very large program. I beleive that monks can definitely clear my doubts. 

$_ = foo; /foo/;

# prints "bar\n"
for (qw/bar baz/) { print "$&\n" unless /bar/; } 

# prints "foo\n"
for (qw/bar baz/) { next if /bar/; print "$&\n"; }

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In reply to The value of pattern match variable $& by jesuashok

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