Hello Monks,

I have tried to find an answer on this issue for the past day or so. I saw a similar thread: Value of a scalar specified by a second scalar ,but still came out empty handed. My problem child is here:

chomp($exp = <STDIN>); $out = 'exp'; print $$out, "\n";

I'm not sure if referencing is the proper thing to do here since I am getting an "unitialized variable" here. The <STDIN> is an expression along the lines of:

(7 * 3) + (2 + 1)

I am trying to get this block to return the answer, which in this case is "24". When I just do:

print "$exp\n"

I get the expression back and not the answer. I was hoping I could get a few pointers on this.


thank you in advance.

Es gibt mehr im Leben als Bücher, weißt du. Aber nicht viel mehr. - (Die Smiths)

In reply to Chomp a numerical expression, return the answer. by sub_chick

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