You are basically right, however I don't think this line is correct.
print a({-href => $dangerous}, escapeHTML($dangerous));
in this case, you have to uri-escape the filename except for the slashes. Suppose for example that the filename is
"a?b<c". Than the above example would print
<a href="a?b<c">a?b<c</a>. When the viewer clicks on the link, the browser will html-unescape the attribute, and load
a?b<c prepended with the current base url. The web server would however interpret this as loading the file
a with the GET parameter being
b<c. The code should have instead printed
<a href="a%3Fb%3Cc">a?b<c</a>.
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