Thank You, everyone for your help! I am just confused with the following example. I think it is an inverted form of the original example I performed: 
%HoA = (
        flintstones        => [ "fred", "barney" ],
        jetsons            => [ "fred", "jane", "elroy" ],
        simpsons           => [ "fred", "marge", "bart" ],
      );

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If the family names (jetsons, simpsons) are always different but elements within each of the familes may or may not match. If I want to show that: 
"fred" is a name that can be found in 3 families = [flintstones, jetso
+ns, simpsons]
e.t.c

[download]
Is this possible with this hash formation?

In reply to Re^2: Counting Data in two columns? by sdslrn123
in thread Counting Data in two columns? by sdslrn123

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