Guys: Sorry about that. I missed when he said "something like that", which means not exactly it. I am supposed to make it work... Ok so, it is now working. Here is what I have (not exactly...). ;-) 
sub isbitset {

   my $bytetocheck = $_[0];
   my $bittocheck = $_[1];

   if (($bytetocheck >> $bittocheck) & 1) {
      return 1;
   } else {
      return 0;
   }

} # End of isbitset function.

##################################################
# I am testing all 8 bits to see which one is set.
##################################################
printf ("\tByte %08b bit 0 => %d\n\n", 
      ord $uh[0], &isbitset((ord $uh[0]), 0));

printf ("\tByte %08b bit 1 => %d\n\n", 
      ord $uh[0], &isbitset((ord $uh[0]), 1));

printf ("\tByte %08b bit 2 => %d\n\n", 
      ord $uh[0], &isbitset((ord $uh[0]), 2));

printf ("\tByte %08b bit 3 => %d\n\n", 
      ord $uh[0], &isbitset((ord $uh[0]), 3));

printf ("\tByte %08b bit 4 => %d\n\n", 
      ord $uh[0], &isbitset((ord $uh[0]), 4));

printf ("\tByte %08b bit 5 => %d\n\n", 
      ord $uh[0], &isbitset((ord $uh[0]), 5));

printf ("\tByte %08b bit 6 => %d\n\n", 
      ord $uh[0], &isbitset((ord $uh[0]), 6));

printf ("\tByte %08b bit 7 => %d\n\n", 
      ord $uh[0], &isbitset((ord $uh[0]), 7));

[download]
Is it looking any better? Thanks, RV

In reply to Re: Help comparing data in byte by shifting (>>) bits by unixhome
in thread Help comparing data in byte by shifting (>>) bits by unixhome

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