Hi jithoosin,

It depends on which "?" you mean.

The typical use of "?" in a regex is "zero or one" of the preceding thing.Of course, another way to say "zero or one", is "optional".  So, for example, in "(?:\?.*)?", the final "?" means that "(?:\?.*)" is optional.

The second "?" (in "\?") stands for a single "?" (since it's escaped with "\").

However, the first "?":  :"(?:...)" has a different meaning, which is that it turns off the "capture" that would usually happen with "(...)".

You should read more about perl regular expressions to get the full scoop.

s''(q.S:$/9=(T1';s;(..)(..);$..=substr+crypt($1,$2),2,3;eg;print$..$/

In reply to Re: questions of a perl beginner on regex by liverpole
in thread questions of a perl beginner on regex by jithoosin

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