Perl is designed to make string and numeric scalars indistinguishable. It also has a '++' (increment) operator which not only works on numerical strings as well as numbers, but on any string. e.g.
$x = 1; ++$x; # produces 2 or "2" (transparent which) $x = "1"; ++$x; # the same $x = "A"; ++$x; # produces B
To strip leading zeros:
$char =~ s/^(0)+//;
see the perlop documentation for more details.

-M

Free your mind


In reply to Re: adding 1 to a char of 1 by Moron
in thread adding 1 to a char of 1 by Anonymous Monk

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